Pozdrawiam

DeCha

W dniu 2014-05-07 14:57, Rafał Ramocki pisze:

select c.name, lastname, city, zip, address, count(n.id), n.name, passwd FROM customers c LEFT JOIN nodes n ON n.ownerid = c.id WHERE deleted=0 GROUP BY c.id;

dzięki

--
Interconnect Sp.j.
R. Wróbel, K. Gambuś
ul. 1 Maja 84
42-660 Kalety
KRS 0000329294
tel. 507118259

_______________________________________________
lms mailing list
lms@lists.lms.org.pl
http://lists.lms.org.pl/mailman/listinfo/lms