
12 Kwi
2007
12 Kwi
'07
14:20
Bialy napisał(a):
tutaj wszystko ok, do kompletu podaj jeszcze
SELECT * FROM tariffs; SELECT a.customerid AS id, SUM(uprate) AS uprate, SUM(upceil) AS upceil, SUM(downrate) AS downrate, SUM(downceil) AS downceil
FROM assignments a
LEFT JOIN tariffs ON (a.tariffid = tariffs.id) WHERE EXISTS (SELECT 1 FROM nodeassignments JOIN nodes n ON (n.id = nodeid) WHERE a.id = assignmentid AND n.access = 1) GROUP BY a.customerid;
--
Aleksander 'A.L.E.C' Machniak http://alec.pl gg:2275252
LAN Management System Developer http://lms.org.pl
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