8 Lis
2007
8 Lis
'07
13:49
ICE wrote:
klientów czy ich komputery?
chodzi oczywiscie o klientow,a nie o ich komputery ;)
spróbuj jakoś tak:
SELECT DISTINCT c.id, c.lastname, c.name, COALESCE(cash.balance, 0)
FROM customers c
JOIN customerassignments a ON (a.customerid = c.id) LEFT JOIN ( SELECT SUM(value) AS balance, customerid FROM cash GROUP BY customerid ) cash ON (cash.customerid = c.id) WHERE a.customergroupid IN (3,5,25) OR (a.customerid = 4 AND (cash.balance != 0 AND cash.balance IS NOT NULL))
--
Aleksander 'A.L.E.C' Machniak http://alec.pl gg:2275252
LAN Management System Developer http://lms.org.pl
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