On Sun, 14 Sep 2003, A.L.E.C wrote:

SELECT users.id AS id, SUM((type * 2 - 7) * value) AS balance FROM users LEFT JOIN cash ON users.id = cash.userid WHERE (cash.type = 3 OR cash.type = 4) AND users.status = 3 GROUP BY users.id

takie zapytanie zwraca wszystkie rekordy... lacznie z tymi co users.status maja <> 3.

Pozdrawiam Pawel Bernadowski GG 3377, email kontakt@pbern.biz